Bei Enter nächte Textbox springen

Hi,

Ich möchte, wenn ich in eine Textbox einen Text eingebe und [Enter] drücke, das das Fenster nicht geschlossen wird, sondern in die 2. Textbox gesprungen wird.

Mein Script:

Add-Type -AssemblyName System.Windows.Forms
Add-Type -AssemblyName System.Drawing

$form = New-Object System.Windows.Forms.Form
$form.Text = 'Data Entry Form'
$form.Size = New-Object System.Drawing.Size(300,200)
$form.StartPosition = 'CenterScreen'

$okButton = New-Object System.Windows.Forms.Button
$okButton.Location = New-Object System.Drawing.Point(75,120)
$okButton.Size = New-Object System.Drawing.Size(75,23)
$okButton.Text = 'OK'
$okButton.DialogResult = [System.Windows.Forms.DialogResult]::OK
$form.AcceptButton = $okButton
$form.Controls.Add($okButton)

$cancelButton = New-Object System.Windows.Forms.Button
$cancelButton.Location = New-Object System.Drawing.Point(150,120)
$cancelButton.Size = New-Object System.Drawing.Size(75,23)
$cancelButton.Text = 'Cancel'
$cancelButton.DialogResult = [System.Windows.Forms.DialogResult]::Cancel
$form.CancelButton = $cancelButton
$form.Controls.Add($cancelButton)

$label = New-Object System.Windows.Forms.Label
$label.Location = New-Object System.Drawing.Point(10,20)
$label.Size = New-Object System.Drawing.Size(280,20)
$label.Text = 'Please enter the information in the space below:'
$form.Controls.Add($label)

$textBox = New-Object System.Windows.Forms.TextBox
$textBox.Location = New-Object System.Drawing.Point(10,40)
$textBox.Size = New-Object System.Drawing.Size(260,20)
$textBox.Add_Validating({
                $this.TopLevelControl.Tag += $this.Text
            })
$form.Controls.Add($textBox)

$textBox2 = New-Object System.Windows.Forms.TextBox
$textBox2.Location = New-Object System.Drawing.Point(10,60)
$textBox2.Size = New-Object System.Drawing.Size(260,20)
$textBox2.Add_Validating({
                $this.TopLevelControl.Tag += $this.Text
            })
$form.Controls.Add($textBox2)


$form.Topmost = $true

$form.Add_Shown({$textBox.Select()})
$result = $form.ShowDialog()

if ($result -eq [System.Windows.Forms.DialogResult]::OK)
{
    $x = $form.Tag
    $x
}